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(1/9)^x-5=3^x
We move all terms to the left:
(1/9)^x-5-(3^x)=0
Domain of the equation: 9)^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/9)^x-3^x-5=0
We multiply all the terms by the denominator
(+1-3^x*9)^x-5*9)^x=0
Wy multiply elements
(+1-3^x*9)^x-45x=0
We add all the numbers together, and all the variables
-45x+(+1-3^x*9)^x=0
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